JPexam CIWの1D0-541試験トレーニング資料というのは一体なんでしょうか。CIWの1D0-541試験トレーニングソースを提供するサイトがたくさんありますが、JPexamは最実用な資料を提供します。JPexamには専門的なエリート団体があります。認証専門家や技術者及び全面的な言語天才がずっと最新のCIWの1D0-541試験を研究していますから、CIWの1D0-541認定試験に受かりたかったら、JPexamのサイトをクッリクしてください。あなたに成功に近づいて、夢の楽園に一歩一歩進めさせられます。
JPexamのCIWの1D0-541試験トレーニング資料は全てのオンラインのトレーニング資料で一番よいものです。我々の知名度はとても高いです。これは受験生の皆さんが資料を利用した後の結果です。JPexamのCIWの1D0-541試験トレーニング資料を選んだら、１００パーセントの成功率を保証します。もし失敗だったら、我々は全額で返金します。受験生の皆さんの重要な利益が保障できるようにJPexamは絶対信頼できるものです。
試験番号：1D0-541問題集
試験科目：CIW v5 Database Design Specialist
最近更新時間：2014-03-03
問題と解答：全124問
100％の返金保証。1年間の無料アップデート。
JPexamは初めて試験を受けるあなたが一回で試験に合格して、認証資格を取ることを保証します。JPexamが提供して差し上げたのは高品質のCIWの1D0-541模擬問題集で、あなたがステップバイステップで試験に準備する手順を指導しています。JPexamのCIWの1D0-541試験問題集は絶対あなたに成功をもたらすことを保証します。JPexamのCIWの1D0-541認定試験に準備するために色々な方法がありますが、
あなたはいまCIWの1D0-541認定試験にどうやって合格できるかということで首を傾けているのですか。CIWの1D0-541認定試験は現在のいろいろなIT認定試験における最も価値のある資格の一つです。ここ数十年間では、インターネット・テクノロジーは世界中の人々の注目を集めているのです。それがもう現代生活の不可欠な一部となりました。その中で、CIWの認証資格は広範な国際的な認可を得ました。ですから、IT業界で仕事している皆さんはCIWの認定試験を受験して資格を取得することを通して、彼らの知識やスキルを向上させます。1D0-541認定試験はCIWの最も重要な試験の一つです。この資格は皆さんに大きな利益をもたらすことができます。
JPexamは CIWの1D0-541認定試験の認証に対して特別な教育ツールで、あなたに多くの時間とお金が使わないようにIT技術にも身につけさせるサイトでございます。JPexamは専門家チームが自分の知識と経験をを利用してCIWの1D0-541認証試験の問題集を研究したものでございます。
購入前にお試し,私たちの試験の質問と回答のいずれかの無料サンプルをダウンロード：http://www.jpexam.com/1D0-541_exam.html
NO.1 Consider the entity-relation (ER) diagram shown in the exhibit. When the logical database design phase
is completed, which of the following is a valid DBDL description of the base relations for the ER diagram?
A.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name: integer NOT
NULL) Primary Key Class_Num
B.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name: integer NOT
NULL) Primary Key Class_Num Foreign Key Class_Num References STUDENT
C.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number STU_CLASS( Student_Number: integer NOT NULL Class_Num:
integer NOT NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name:
integer NOT NULL) Primary Key Class_Num
D.STUDENT( Student_Number: integer NOT NULL Name: variable length character string length 20 NOT
NULL) Primary Key Student_Number STU_CLASS( Student_Number: integer NOT NULL Class_Num:
integer NOT NULL) Primary Key Student_Number CLASS( Class_Num: integer NOT NULL Class_Name:
integer NOT NULL) Primary Key Class_Num
Answer:D
CIW参考書 1D0-541過去問 1D0-541
NO.2 Consider the following SQL statement and the Orders relation shown in the exhibit: What is the output
of this SQL statement? Answer & Explanation Correct Answer C Explanations No more information
available
Answer:
NO.3 What is the highest normal form of the relation(s) shown in the exhibit?
A.Second normal form
B.First normal form
C.Boyce-Codd normal form
D.Third normal form
Answer:A
CIW認定試験 1D0-541 1D0-541参考書 1D0-541
NO.4 The exhibit shows a table called Student Relation that tracks all information related to a students
courses, professors and sites. What would be the consequence of removing all records for a student with
the ID 1311?
A.Only an update anomaly would occur.
B.An insertion anomaly would occur.
C.A deletion anomaly would occur.
D.An update anomaly and a deletion anomaly would occur.
Answer:C
CIW 1D0-541 1D0-541練習問題 1D0-541参考書
NO.5 Which of the following best describes a composite key?
A.A composite key is a primary key and foreign key that consists of the first two attributes of a relation.
B.A composite key is a primary or foreign key defined by its parent key attributes.
C.A composite key is a foreign key that consists of the same attributes as the primary key from a related
table.
D.A composite key is a primary or foreign key that consists of two or more attributes of a relation.
Answer:D
CIW 1D0-541 1D0-541過去問
NO.6 Consider the Information Engineering diagram in the exhibit showing a conceptual data model of the
relations BUILDING and RESIDENT. What is the next step in refining the data model?
A.Create intermediate entities.
B.Create a logical data model.
C.Resolve many-to-many relationahips.
D.Identify and resolve complex relationships.
Answer:B
CIW 1D0-541認定試験 1D0-541練習問題 1D0-541認定試験
NO.7 Consider the following relation definition: STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 NOT NULL) Primary Key Student_Number
HOUSING( Housing_ID: integer NOT NULL Student_Number: integer NOT NULL Building: variable
length character string length 25 NOT NULL) Primary Key Housing_ID Foreign Key Student_Number
References STUDENT(Student_Number) ON DELETE NO CHECK ON UPDATE Which integrity
constraint is violated in this relation definition?
A.Entity integrity
B.Domain constraint
C.Referential integrity
D.Enterprise constraint
Answer:C
CIW問題集 1D0-541問題集 1D0-541 1D0-541 1D0-541認定試験
NO.8 Consider the Recreation relation in the exhibit. A data operation that changes one of the tuples for
Student_ID 1003 must be performed. It is necessary to change one of the activities from swimming to
tennis. The Student_ID and Activity attributes make up the primary key for the Recreation relation. All
related information must be altered, as well. Which SQL statement or statements would best accomplish
this?
A.UPDATE Recreation SET Activity, Activity_Fee ('Tennis', 100) WHERE Student_ID = 1003;
B.UPDATE TABLE Recreation SET ACTIVITY = 'Tennis', Activity_Fee = 100 WHERE Student_ID = 1003
AND Activity = Swimming;
C.UPDATE Recreation SET Activity = 'Tennis', Activity_Fee = 100 WHERE Student_ID = 1003 AND
Activity = 'Swimming';
D.DELETE Activity FROM Recreation WHERE Student_ID = 1003; INSERT INTO Recreation VALUES
(1003, 'Tennis', 100);
Answer:C
CIW 1D0-541練習問題 1D0-541 1D0-541
NO.9 Which characteristic is an advantage of a database management system?
A.Data files are owned and maintained by the users.
B.Database administration is simplified.
C.A standard method can be used to access the database.
D.Data is decentralized.
Answer:C
CIW認証試験 1D0-541 1D0-541 1D0-541
NO.10 Which process is used to prevent the current database operation from reading or writing a data item
while that data item is being accessed by another operation?
A.Lock
B.Deadlock
C.Timestamp
D.Batch
Answer:A
CIW 1D0-541 1D0-541 1D0-541 1D0-541参考書
NO.11 Which relational algebraic operation is used to select specific columns (attributes) from a relation?
A.Union
B.Difference
C.Projection
D.Intersection
Answer:C
CIW 1D0-541 1D0-541認定試験 1D0-541認定証 1D0-541
NO.12 Consider the Registration relation shown in the exhibit. Which of the following SQL statements would
return all tuples that have course codes beginning with the letter M?
A.SELECT * FROM Registration WHERE Course_Code = M#;
B.SELECT * FROM Registration WHERE Course_Code LIKE M_;
C.SELECT * FROM Registration WHERE Course_Code LIKE M%;
D.SELECT * FROM Registration WHERE Course_Code = M%;
Answer:C
CIW過去問 1D0-541認定証 1D0-541 1D0-541 1D0-541
NO.13 Which of the following occurs in a relation when records are added or removed?
A.The number of domains changes.
B.The attributes in the table change.
C.The cardinality of the relation is fixed but the degree varies.
D.The degree of the relation is fixed but the cardinality varies.
Answer:D
CIW 1D0-541練習問題 1D0-541 1D0-541 1D0-541認定証
NO.14 Which of the following best describes the information contained in the data dictionary (or system
catalog)?
A.Metadata
B.Data model
C.Table data
D.Metafile
Answer:A
CIW認定証 1D0-541問題集 1D0-541 1D0-541認定証
NO.15 Which pair of relational algebraic operations requires union compatibility?
A.Projection and Cartesian product
B.Selection and projection
C.Intersection and difference
D.Cartesian product and intersection
Answer:C
CIW 1D0-541認証試験 1D0-541
NO.16 Consider the following four database design activities: 1 - Design user views. 2 - Select a DBMS. 3 -
Apply normalization. 4 - Determine entities. Which choice shows the correct ordering of these activities,
from first to last, by assigned numbers?
A.1, 2, 3, 4
B.3, 4, 1, 2
C.4, 1, 3, 2
D.4, 2, 3, 1
Answer:D
CIW 1D0-541認定資格 1D0-541参考書
NO.17 Consider the following relation definitions: STUDENT( Student_Number: integer NOT NULL Name:
variable length character string length 20 ) Primary Key Student_Number HOUSING( Housing_ID: integer
NOT NULL Student_Number: integer NOT NULL Building: variable length character string length 25 )
Primary Key Housing_ID Foreign Key Student_Number References STUDENT(Student_Number) ON
DELETE NO ACTION ON UPDATE CASCADE What are the referential constraints for the relations
defined in these relation definitions?
A.There is no relationship between changes in STUDENT(Student_Number) and
HOUSING(Student_Number).
B.When STUDENT(Student_Number) is changed or deleted, this modification or deletion will
automatically be reflected in HOUSING(Student_Number).
C.Modifications to HOUSING(Student_Number) are automatically reflected in changes to
STUDENT(Student_Number), but deletions are not permitted.
D.Modifications to STUDENT(Student_Number) are automatically reflected in changes to
HOUSING(Student_Number). For a deletion to occur from STUDENT(Student_Number), it must first
occur in HOUSING(Student_Number).
Answer:D
CIW認定証 1D0-541問題集 1D0-541認定試験 1D0-541認定証
NO.18 Which of the following describes two desirable characteristics of a primary key?
A.A primary key should be a value that may be null and may change over time.
B.A primary key should be a value that is not null and will never change.
C.A primary key should consist of meaningful data and a value that can be changed if needed.
D.A primary key should not consist of meaningful data and a value that can be changed if needed.
Answer:B
CIW 1D0-541 1D0-541 1D0-541過去問
NO.19 Your enterprise is involved in planning a database project. The exhibit shows the result of one phase of
the database design life cycle. Which term best describes the diagram shown in the exhibit?
A.Information Engineering (IE) data model
B.Corporate data model
C.Database requirements model
D.Entity Relation Data (ERD) model
Answer:B
CIW練習問題 1D0-541認定資格 1D0-541 1D0-541 1D0-541練習問題
NO.20 Consider the following relations shown in the exhibit. Which of the following SQL statements would
return the Customers2 relation from the Customers relation?
A.SELECT * FROM Customers WHERE Satisfaction_Rate <= 80 OR Satisfaction_Rate >= 90;
B.SELECT * FROM Customers WHERE Satisfaction_Rate IN (80 AND 90);
C.SELECT * FROM Customers WHERE Satisfaction_Rate >= 80 AND Satisfaction_Rate <= 89;
D.SELECT * FROM Customers WHERE Satisfaction_Rate BETWEEN (80, 90);
Answer:C
CIW問題集 1D0-541認定証 1D0-541 1D0-541 1D0-541練習問題 1D0-541認定資格
JPexamは最新のHP0-J63問題集と高品質のCAT-380問題と回答を提供します。JPexamのHP2-T23 VCEテストエンジンとJN0-643試験ガイドはあなたが一回で試験に合格するのを助けることができます。高品質のHP3-C33 PDFトレーニング教材は、あなたがより迅速かつ簡単に試験に合格することを100％保証します。試験に合格して認証資格を取るのはそのような簡単なことです。
没有评论:
发表评论